can someone explain how to do this problem, i got the first part correct but i dont understand how to get the area exactly. THanks!
Consider the points below. P(1, 0, 0), Q(0, -2, 0), R(0, 0, -3)
(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
Enter a number.
6i + Enter a number.
-3
-2
(b) Find the area of the triangle PQR.
Enter an exact number as an integer fraction or decimal.
3
NVM I FIGURED IT OUT THANKS FOR LOOKING AT IT!!
It will be half of the magnitude of the cross product of PQ and RQOriginally Posted by ahawk1
can someone explain how to do this problem, i got the first part correct but i dont understand how to get the area exactly. THanks!
Consider the points below. P(1, 0, 0), Q(0, -2, 0), R(0, 0, -3)
(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
Enter a number.
6
-3
-2
(b) Find the area of the triangle PQR.
Enter an exact number as an integer fraction or decimal.
3
and
Now we take half of the magnitude to get
^2+(3)^2+(2)^2}=\frac{1}{2}\sq rt{49}=\frac{7}{2})
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