Ok we are differentiating.. 2x^2e^3dx (2x Squared EX Cubed...having problems with the math /math thing) My answer is 3xe^x^3 (3xe x cubed)
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Originally Posted by Chris Ok we are differentiating.. 2x^2e^3dx (2x Squared EX Cubed...having problems with the math /math thing) My answer is 3xe^x^3 (3xe x cubed) $\displaystyle f(x) = 2x^2e^3 $ We know 2eł is a constant so it's the same as $\displaystyle f(x) = 2e^3(x^2)$ Differentiating we get $\displaystyle 2x \times 2e^3 = 4xe^3$
Last edited by e^(i*pi); Apr 25th 2009 at 03:39 PM. Reason: because 2x2 = 4 not 6 -facepalm-
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