# Math Help - conv. and div. by comparison

1. ## conv. and div. by comparison

just a question:

while using comparisons to decide whether the integral converges or diverges

we know that 1/x div
1/x^2 conv

2. Originally Posted by alex83
just a question:

while using comparisons to decide whether the integral converges or diverges

we know that 1/x div
1/x^2 conv
ask yourself this question for $x>1$
$\frac{1}{x^2}$ and $\frac{1}{x^3}=\frac{1}{x^2}\frac{1}{x}$