What is integral of line ? How do I calculate? Example: C is segment of straight of (0,0) until (0,1). How do I calculate: $\displaystyle \int_C senxy dy$
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Originally Posted by Apprentice123 What is integral of line ? How do I calculate? Example: C is segment of straight of (0,0) until (0,1). How do I calculate: $\displaystyle \int_C senxy dy $ What is "sen" ?
Sory in english $\displaystyle sin$
Just substitute x=0 (y from 0 to 1) into the integral and integrate along the y axis.
The answer this integral is 0 ? And the intregral line $\displaystyle \int_C 3x^2yzds$ $\displaystyle C: x = t, y = t^2, z = \frac{2}{3}z^3$ $\displaystyle 0 \leq t \leq 1$ The answer is $\displaystyle \frac{197}{180}$ ???
Originally Posted by Apprentice123 The answer this integral is 0 ? And the intregral line $\displaystyle \int_C 3x^2yzds$ $\displaystyle C: x = t, y = t^2, z = \frac{2}{3}z^3$ $\displaystyle 0 \leq t \leq 1$ The answer is $\displaystyle \frac{197}{180}$ ??? $\displaystyle z = \frac{2}{3}t^3$ ? I think the answer is $\displaystyle \frac{13}{20}$
Last edited by curvature; Apr 25th 2009 at 06:57 AM.
The first integral $\displaystyle \int_C sinxy dy$ the answer is 0 ? And the other integral where you resolved ?
[quote=Apprentice123;304717]The first integral $\displaystyle \int_C sinxy dy$ the answer is 0 ? quote] Yes. Because sinxy=0 on the line x=0.
In $\displaystyle \int_C 3x^2yzds$ $\displaystyle C: x = t, y = t^2, z = \frac{2}{3}t^3$ $\displaystyle 0 \leq t \leq 1$ how you found $\displaystyle \frac{13}{20}$ ?
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