1. ## Optimization help

Consider a window the shape of which is a rectangle of height surmounted a triangle having a height that is 1.5 times the width of the rectangle.

I think over all area will equal

A=w*h+1/2(w*h)

For the rectangle
A=w*h (obviously)
Perimeter = 2w+2h

Triangle
A=1/2w*t
Then i turned the triangle into a right triangle by cutting it in half.
and then to solve for the triangle side we have
z^2=(x/2)^2+t^2

I am not sure where to go from here

2. Originally Posted by Casas4
Consider a window the shape of which is a rectangle of height h surmounted a triangle having a height T that is 1.5 times the width w....
Once you've "considered" the window, what are you supposed to do with it?

I see where you've done some "area" stuff, but that's just geometry. Your subject line refers to "optimization", which is calculus. But what were the instructions? What calculus-type stuff are you supposed to do?

Thank you!

3. Oh I'm sorry "If the cross-sectional area is A, determine the dimensions of the window which minimize the perimeter.? So I have to minimize the perimeter.