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Math Help - Find derivative (dF/dt)

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    Find derivative (dF/dt)

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    Quote Originally Posted by zaurm View Post
    Let G be an antiderivative of sin.

    Then by definition of the integral, F(x)=G(x^2)-G(1)
    If you differentiate, by applying the chain rule, you get :
    \frac{dF}{dx}=2xG'(x^2) (the derivative of G(1) is 0 because it's a constante)

    But by definition, G' is sin.

    So \frac{dF}{dx}=2x\sin(x^2)
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