http://i39.tinypic.com/nnqgk8.jpg
I got something close to the second choice but not exact.
Can you show how you got it?
http://i39.tinypic.com/nnqgk8.jpg
I got something close to the second choice but not exact.
Can you show how you got it?
$\displaystyle y=\sin\!\left(x+y\right)$
By implicit differentiation [and chain rule], we have $\displaystyle \frac{\,dy}{\,dx}=\cos\!\left(x+y\right)\cdot\left (1+\frac{\,dy}{\,dx}\right)\implies \frac{\,dy}{\,dx}=\cos\!\left(x+y\right)+\cos\!\le ft(x+y\right)\frac{\,dy}{\,dx}$
Can you finish off the problem?