f ' (x)= ( f(x)-f(xo) )/ (x-xo)
this implies..
f(x)-f(xo) = f ' (x) (x-xo)
Hello, zaurm!
We have: .Use differentials to approximate the change in
.if changes from 1 to 1.02
. . And: .
Therefore: .
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
I like to check my answer by calculating the actual change.
. .
. .
The actual change is: .
. . . . Close enough!