# Math Help - Work done

1. ## Work done

A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done in compressing the spring an additional 3 inches.

2. You're asking far too many questions. It would do no good for us to help you if you honestly don't know what you're doing with any of them.

I want you to think this problem through and we'll build on it.

work = force * distance

3. i know how to start them and i get anwsers but i don't know if they are right.

4. integrate from 0 to 6 750x dx=13500N?

5. They seem to want you to assume a lot. Not really sure why this is even a calc question.

On a force-distance graph, y = 750 when x = 3 and y = 0 when x = 0.

The integral of a force-distance graph gives you force*distance, or work.

So we have

$W(3) - W(0) = \int_{0}^{3} F(x)dx = Fd = 750*3 = 2250$

And we want

$W(6) - W(3)$

We know that W(0) is 0, so W(3) must be 2250.