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Math Help - Work done

  1. #1
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    Work done

    A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done in compressing the spring an additional 3 inches.
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  2. #2
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    You're asking far too many questions. It would do no good for us to help you if you honestly don't know what you're doing with any of them.

    I want you to think this problem through and we'll build on it.

    work = force * distance
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  3. #3
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    i know how to start them and i get anwsers but i don't know if they are right.
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  4. #4
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    integrate from 0 to 6 750x dx=13500N?
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  5. #5
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    They seem to want you to assume a lot. Not really sure why this is even a calc question.

    On a force-distance graph, y = 750 when x = 3 and y = 0 when x = 0.

    The integral of a force-distance graph gives you force*distance, or work.

    So we have

    W(3) - W(0) = \int_{0}^{3} F(x)dx = Fd = 750*3 = 2250

    And we want

    W(6) - W(3)

    We know that W(0) is 0, so W(3) must be 2250.
    Last edited by derfleurer; April 22nd 2009 at 12:55 PM.
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