Hello, sorry i cant learn latex 0 to (2sgrt3)S(sgrt(16-x^2)-2)dx=? S=integ. i want to see solution way then i can solve ...Thanks for all help
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Originally Posted by bebrave Hello, sorry i cant learn latex 0 to (2sgrt3)S(sgrt(16-x^2)-2)dx=? S=integ. i want to see solution way then i can solve ...Thanks for all help The first quotient will give an arcsin-function, the second quotient has to be integrated by partial integration and integration by substitution.
i think this way, x=4sint-->dx=4cost.dt x=0==>sint=0==>t=0 x=2sgrt3==>sint=(sgrt3)/2==>t=x/3 so 0 to pi/3 S(sgrt(16-16sin^2t)-2)4cost.dt 0 to pi/3 S(4cost-2)4cost.dt 0 to pi/3 S(16cos^2t-8cost)dt then
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