Hello,
sorry i cant learn latex
0 to (2sgrt3)S(sgrt(16-x^2)-2)dx=?
S=integ.
i want to see solution way then i can solve ...Thanks for all help
$\displaystyle \int_0^{2\sqrt{3}}\left(\sqrt{16-x^2} - 2\right)dx=\int_0^{2\sqrt{3}}\left(\dfrac{16-x^2}{\sqrt{16-x^2}} - 2\right)dx =$ $\displaystyle \int_0^{2\sqrt{3}}\left(\dfrac{16}{\sqrt{16-x^2}}-\dfrac{\frac12 x \cdot 2x}{\sqrt{16-x^2}} - 2\right)dx =$
The first quotient will give an arcsin-function, the second quotient has to be integrated by partial integration and integration by substitution.