need help...is the func. diff at x=0 or not?
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Originally Posted by adhyeta need help...is the func. diff at x=0 or not? Yes. f(x) = x^3 when x > 0 and f(x) = -x^3 when . Therefore f'(x) is continuus at x = 0.
If you compute the derivative of in as... ... for and is... ... no matter which is the sign of . So is differentiable in ... Kind regards
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