g(x)=0 if x is rational g(x)=x if x is irrational for what values of x is g continuous?
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Originally Posted by myoplex11 g(x)=0 if x is rational g(x)=x if x is irrational for what values of x is g continuous? Have you ever heard of "Dirichelt" function? Same idea. The limit that we approach a point bt rationals needs to be the same as we approach the limit by irrationals. In that case is the only continous point. Look Heir
i understand why it is continous a x=0 but i need to justify this mathematically
Originally Posted by myoplex11 i understand why it is continous a x=0 but i need to justify this mathematically Choose any and set , then whenever , hence is continuouse at . RonL
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