trying to take the integral of cos^2(3x)
but since I can take that integral, I need to change it up. just need to know if I'm doing this correctly.. I'm getting..
1/2 + 1/2cos(6x)
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Let u = 3x du = 3dx
1/3integral(cos^2(u)) = 1/3 (u/2 +1/4sin(u))= x/2 +1/12[sin(3x)]
Of course my answer should have been 1/3 (u/2 +1/4 sin(2u) )=
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