Thread: Integration

y = (1/10)coshxarctan(sinhx)

Find the integral of coshxarctan(sinhx) dx

How should i approach this?

Hello,

Originally Posted by Erghhh

y = (1/10)coshxarctan(sinhx)

Find the integral of coshxarctan(sinhx) dx

How should i approach this?

Notice that the derivative of sinh(x) is precisely cosh(x)
In this case, substitution is the best way.

Substitute t=sinh(x) : it will eliminate cosh(x)

Then, you're left with the integral of arctan(t)
which can be done with an integration by parts, or again an substitution : t=tan(u)

Don't forget to substitute back once you're finished !