y = (1/10)coshxarctan(sinhx)
Find the integral of coshxarctan(sinhx) dx
How should i approach this?
Hello,
Notice that the derivative of sinh(x) is precisely cosh(x)
In this case, substitution is the best way.
Substitute t=sinh(x) : it will eliminate cosh(x)
Then, you're left with the integral of arctan(t)
which can be done with an integration by parts, or again an substitution : t=tan(u)
Don't forget to substitute back once you're finished !