The region R in the first quadrant that is bounded by the graphs of y=x^3, y=4x, and y=-2x+3=0 and that lies below both straight lines. Find the area of this region.

I tried to find the area of the bigger triangle-the smaller region:

I took the integral of -6x+3 from 0 to 1.5 and got -2.25

then i took the integral of -x^3-2x+3 and got .984375

Altogether I get -3.234375. Is this right?