Find $\displaystyle \frac{dy}{dx}$

$\displaystyle x = \frac{2}{t}$

$\displaystyle y = \sqrt{t}e^{-t}$

$\displaystyle x' = 2ln(t)$

$\displaystyle y' = \frac{1-2t}{2\sqrt{t}e^t}$

$\displaystyle \frac{dy}{dx} = \frac{1-2t}{4\sqrt{t}ln(t)e^{2t}}$

This is wrong, can someone tell me where I am wrong?

Thanks!