Ok, so what you need to do is to take the integral of the minus
So, it'll look like this:
there ya are, have fun
Find the area of the region that lies inside the curve r=1 + cosΘ and outside of the curve r= 3cosΘ
I set them equal to eachother and solved for Θ = pi/3, 5pi/3
I then set up the integral from pi/3 to pi of (0.5)(1+cosΘ)^2 and got
pi - [8+rad(3)]/8
can anyone help me solve this problem
thanks
You didn't like my work before? lol. Ok, so to do it correctly this time. The trick is that the function will need to be integrated from whereas the other function needs to be integrated from
This actually comes out very nicely:
there ya go. That's the correct formula and the correct answer.