how do i figure out the derivative of this? y= ln(sqrt 2x^2+2)
Follow Math Help Forum on Facebook and Google+
Originally Posted by foodmmm how do i figure out the derivative of this? y= ln(sqrt 2x^2+2) If you mean $\displaystyle y=\ln(\sqrt{2x^2+2})=\frac{1}{2}\ln(2x^2+2)$ Now taking the derivative we get $\displaystyle y'=\frac{1}{2}\cdot \frac{1}{2x^2+2}\cdot (4x)=\frac{x}{x^2+1}$
View Tag Cloud