1. ## derivative help

how do i figure out the derivative of this?

y= ln(sqrt 2x^2+2)

2. Originally Posted by foodmmm
how do i figure out the derivative of this?

y= ln(sqrt 2x^2+2)
If you mean

$y=\ln(\sqrt{2x^2+2})=\frac{1}{2}\ln(2x^2+2)$

Now taking the derivative we get

$y'=\frac{1}{2}\cdot \frac{1}{2x^2+2}\cdot (4x)=\frac{x}{x^2+1}$