I know this integral is an integration by parts, but what is the correct approach to breaking it up so that it becomes solvable? $\displaystyle \int{x^5sin(x^3)}$
Follow Math Help Forum on Facebook and Google+
Originally Posted by gammaman I know this integral is an integration by parts, but what is the correct approach to breaking it up so that it becomes solvable? $\displaystyle \int{x^5sin(x^3)}$ $\displaystyle u=x^3 \implies du=3x^2dx$ and $\displaystyle dv=x^2\sin(x^3)dx \implies v=-\frac{1}{3}\cos(x^3)$ You should be able to finish from here
Thanks, but according to my notes u=1/3x^3 du=x^2 dv=3x^2sin(x^3) v=-cos(x^3) does this make sense? Your way seems much more logical.
Originally Posted by gammaman Thanks, but according to my notes u=1/3x^3 du=x^2 dv=3x^2sin(x^3) v=-cos(x^3) does this make sense? Your way seems much more logical. You will get the same answer either way. If you write them out you will see that they are equivilent.
View Tag Cloud