Is it possible to differentiate this equation?

(2x^2)(y)-(7y^2)=(8x)-2y-11 to find y'(1)?

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- Apr 20th 2009, 09:11 AMHakhengkimDifferentiating Implicitly
Is it possible to differentiate this equation?

(2x^2)(y)-(7y^2)=(8x)-2y-11 to find y'(1)? - Apr 20th 2009, 09:18 AMderfleurer
2yx^2 - 7y^2 - 8x + 2y = -11

-(d/dx)/(d/dy)

(8 - 4xy) / (2x^2 - 14y + 2)

y'(1) just accounts for one of those variables, however. You need an x and a y coordinate to perform the calculation. For y'(1), do you mean x by that 1? If so, just plug back into the original equation to get the y value accompanying it.

*Edit*: Missed that 2y', sorry. Fixed - Apr 20th 2009, 09:19 AMHakhengkim
- Apr 20th 2009, 10:25 AMSoroban
Hello, Hakhengkim!

Did you follow derfleurer's advice and finish the problem?

Quote:

. . Find

. .

Factor: .

If , the equation becomes: .

. .

And we have two points: .

At

At

- Apr 20th 2009, 11:15 AMderfleurer
Whoop, missed that + 2 in the denominator.

Not to hijack the thread, but how'd you get 2xy' - 14yy' +2y' = 2(x - 7y - 6)y'?