Can someone please explain this integral;
The integral from 0 to 1 of: 2t(sqrt(1 + 2t^2))dt
I tried using substitution
let u=sqrt(1 + 2t^2)
but I keep getting a different answer than the book...
I like fantastic's method, though since I'm new to the posts, I thought I'd get some practice. So, this is the longer version:
I used 2 substitutions (though you only need one being ), being , du=2tdt and p=1+2u dp=2du so, it should look like this:
*first substitution*
*second substitution*