i am working on some problems involving triple integrals and a lot of them have e^(x+y) but i just don't get how to integrate this with respect to x or y.
can somebody please explain me how this works?
Thanks
You need to bring the 1/constant out too because of integration by parts (or whatever the opposite of the chain rule is)
If x is constant and with respect to y:
$\displaystyle \int e^{x+y}dy = e^{x+y} + C$
If y is constant and with respect to x:
$\displaystyle \int e^{x+y}dx = e^{x+y} + C$
Now, what if i want to integrate ∫∫∫ ze^(x+y) dV to find the mass of the rectangular box determined by 0≤x≤1, 0≤y≤1 and 0≤z≤5.
i tried to solve the integral in the following order..
∫from 0 to 1 ∫from 0 to 1 ∫from 0 to 5 (ze^(x+y))dzdydx
i use the method Calculus 26 described and i got 58.38 but it's wrong!
can you tell mewhat i did wrong, is my set up right?
Thank you