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Math Help - limit where am I going wrong?

  1. #1
    Junior Member
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    limit where am I going wrong?

    as k approaches infinity

    <br /> <br />
ke^{-k^2} =<br />
ke^{1/k^2} =<br />
ke^0 = k = infinity<br /> <br />

    Something is wrong though...
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  2. #2
    MHF Contributor Calculus26's Avatar
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    k*e^(-k^2) = k/e^(k^2) not k*e^(1/k^2)

    one appilcation of L'Hopitals rule gives 0
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  3. #3
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    ok my mistake in logic was with the negative in the power.

    thank you calculus 26
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