as k approaches infinity $\displaystyle ke^{-k^2} = ke^{1/k^2} = ke^0 = k = infinity $ Something is wrong though...
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k*e^(-k^2) = k/e^(k^2) not k*e^(1/k^2) one appilcation of L'Hopitals rule gives 0
ok my mistake in logic was with the negative in the power. thank you calculus 26
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