# limit where am I going wrong?

• April 19th 2009, 09:24 AM
TYTY
limit where am I going wrong?
as k approaches infinity

$

ke^{-k^2} =
ke^{1/k^2} =
ke^0 = k = infinity

$

Something is wrong though...
• April 19th 2009, 09:27 AM
Calculus26
k*e^(-k^2) = k/e^(k^2) not k*e^(1/k^2)

one appilcation of L'Hopitals rule gives 0
• April 19th 2009, 09:41 AM
TYTY
ok my mistake in logic was with the negative in the power.

thank you calculus 26