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Math Help - diff implicit functn

  1. #1
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    diff implicit functn

    Find \frac {\delta y}{\delta x} \, \left ( e^{-y} \right ),

     = e^{-y} \cdot - \frac {\delta y}{\delta x}

     = -e^{-y} \cdot \frac {\delta y}{\delta x}, is this correct?
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  2. #2
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    Quote Originally Posted by ashura View Post
    Find \frac {\delta y}{\delta x} \, \left ( e^{-y} \right ),

     = e^{-y} \cdot - \frac {\delta y}{\delta x}

     = -e^{-y} \cdot \frac {\delta y}{\delta x}, is this correct?
    Looks correct.
    (As long as y is a differenciable function )


    This is my 36th Post!!!
    Last edited by ThePerfectHacker; December 5th 2006 at 10:06 AM.
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  3. #3
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    Quote Originally Posted by ashura View Post
    Find \frac {\delta y}{\delta x} \, \left ( e^{-y} \right ),

     = e^{-y} \cdot - \frac {\delta y}{\delta x}

     = -e^{-y} \cdot \frac {\delta y}{\delta x}, is this correct?
    I don't know what conventions you have been taught, but to me your
    notation doesn't mean anything.

    It looks as though you are asked to find:

    \frac{d}{dx} e^{-y},

    for which:

    \frac{d}{dx} e^{-y} = \frac{dy}{dx}\left(\frac{d}{dy}e^{-y}\right)=-e^{-y}\, \frac{dy}{dx}.

    RonL
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by CaptainBlack View Post
    I don't know what conventions you have been taught, but to me your
    notation doesn't mean anything.

    It looks as though you are asked to find:

    \frac{d}{dx} e^{-y},

    for which:

    \frac{d}{dx} e^{-y} = \frac{dy}{dx}\left(\frac{d}{dy}e^{-y}\right)=-e^{-y}\, \frac{dy}{dx}.

    RonL
    Given the nature of the derivative it's probably not the same, but in Quantum we use that symbol for a functional derivative.

    -Dan
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  5. #5
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    Red face

    Thanks for the correction Ronl.
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