f(x) = ln(5-x) without using maclaurin series
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Originally Posted by twilightstr f(x) = ln(5-x) without using maclaurin series for small $\displaystyle x\ge 0$: $\displaystyle f(x)=- \int_0^x \frac{1}{5-\xi} d\xi $ Now use the binomial expansion for the integrand and integrate term by term. CB
i got ln5 - (1/5) sigma from n= 1 to infinity of (x/5)^n/(n) is this right?
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