no--- a is 0
Rn depends on x -- the max value of x on your interval is .3 So if you're trying to find an upper bound for the error for all x in the interval use .3
To find M I'd do it graphically making sure to use |f^3(x)| on your graph
, ,
Here is my Taylor polynomial approximation:
So, then I found my (n+1) derivative:
So,
CAn someone show me how to do this part?
I know that I need to find a suitable M. How do I do that with these trig fuctions? Can I just choose zero for my x, since it is within my interval?
Thanks!!