1. ## Riemann Sum Help

Hello, if someone could please help me with this problem, I'd really appreciate it. Here's a screenshot, to save the complicated typing:

2. Here $\Delta x = \frac{2}{n}$
and $x_i = \frac{2i}{n}$ so each $x_i$ increases by $\Delta x$ as i increases by 1.

So $R_n = \Sigma_{i=1}^n f(\frac{2i}{n})\frac{2}{n}
=\frac{2}{n} \Sigma_{i=1}^n [(\frac{2i}{n})^2 /2 - 8]$

Is that enough of a start?

3. Originally Posted by Thomas154321
Here $\Delta x = \frac{2}{n}$
and $x_i = \frac{2i}{n}$ so each $x_i$ increases by $\Delta x$ as i increases by 1.

So $R_n = \Sigma_{i=1}^n f(\frac{2i}{n})\frac{2}{n}
=\frac{2}{n} \Sigma_{i=1}^n [(\frac{2i}{n})^2 /2 - 8]$

Is that enough of a start?
Yes, thank you, that did help.