Find the Length of The Curve

y= ln(1 -x2)

0 < x < (1/7)

I got the derivative: (-2x)/(1-x^2)

Then i put it in the formula : sqr*(1+((-2x)/(1-x^2))^2)

My problem seems to be simplifying the terms to cancel the sqr* before integrating.

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- April 17th 2009, 01:59 PMNickytheNineLength of the Curve
*Find the Length of The Curve*

*y*= ln(1 -*x*2)

0 < x < (1/7)

I got the derivative: (-2x)/(1-x^2)

Then i put it in the formula : sqr*(1+((-2x)/(1-x^2))^2)

My problem seems to be simplifying the terms to cancel the sqr* before integrating. - April 17th 2009, 02:03 PMShowcase_22

I'll leave you to put in the limits.

I'm in a bit of a rush, but have you tried integrating it using ? - April 17th 2009, 02:07 PMNickytheNine
0 < x < (1/7)

- April 17th 2009, 02:20 PMNickytheNine
i dont really see how you use a hyperbolic function to make it possible to integrate

- April 17th 2009, 04:18 PMSoroban
Hello, NickytheNine!

It seems you need to brush up on your Algebra . . .

Quote:

Find the length of the curve: .

I got the derivative: .

Then i put it in the formula: .

My problem seems to be simplifying the terms . . .

Under the radical, we have: .

. . . . .

Then: .

And we must integrate and evaluate: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

I recommend long division: .

Got it?

- April 19th 2009, 02:28 PMNickytheNine
thank you very much, i just got to work on my algebra i guess lol