Hi
Is it or y-3)" alt="x = \frac13\:\sqrt{y}\y-3)" /> ?
Having trouble findin the Arc length of this curve.
x=(1/3)(sqr*(y))(y-3) 4<y<25
I found the first derivative: (sqr*(y)/2 - 1/2sqr*(y)) Is that right?
Then put it into the arclength forumule to set up the integral
sqr*(1+ (sqr*(y)/2 - 1/2sqr*(y))^2)
Now sure how to simplify the terms underneath.