Explain what happens to the graph of the function f(x) = logbx when b is equal to 1.

If g(x) = bx and h(x) = logbx, would the graphs of these functions intersect if b = 1? If so, at what ordered pair?

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- Apr 17th 2009, 08:11 AMdesination02Advance Functions. Must See!
Explain what happens to the graph of the function f(x) = logbx when b is equal to 1.

If g(x) = bx and h(x) = logbx, would the graphs of these functions intersect if b = 1? If so, at what ordered pair? - Apr 17th 2009, 08:24 AMJhevon
- Apr 17th 2009, 08:36 AMTwighi
Do you mean $\displaystyle log(b\cdot x) $ ?

If so, if b=1, $\displaystyle log(1 \cdot x) = log(x) $

If $\displaystyle g(x)=b\cdot x \, \mbox{ and } h(x)=log(b\cdot x) $

Now if b=1, then $\displaystyle g(x) = x \mbox{ and } h(x) = log(x) $

g(x) and h(x) does not intersect, look at graph.

Really should try to be more clear in your question, now we donīt know if you mean $\displaystyle log_{1}(x) \mbox{ or } log(x) $