• April 17th 2009, 09:11 AM
desination02
Explain what happens to the graph of the function f(x) = logbx when b is equal to 1.

If g(x) = bx and h(x) = logbx, would the graphs of these functions intersect if b = 1? If so, at what ordered pair?
• April 17th 2009, 09:24 AM
Jhevon
Quote:

Originally Posted by desination02
Explain what happens to the graph of the function f(x) = logbx when b is equal to 1.

If g(x) = bx and h(x) = logbx, would the graphs of these functions intersect if b = 1? If so, at what ordered pair?

is "b" the base of the logarithm here?

note two things: (1) $\log_a b = c \implies a^c = b$

and

(2) $\log_a b = \frac {\log_c b}{\log_c a}$
• April 17th 2009, 09:36 AM
Twig
hi
Do you mean $log(b\cdot x)$ ?
If so, if b=1, $log(1 \cdot x) = log(x)$

If $g(x)=b\cdot x \, \mbox{ and } h(x)=log(b\cdot x)$
Now if b=1, then $g(x) = x \mbox{ and } h(x) = log(x)$

g(x) and h(x) does not intersect, look at graph.

Really should try to be more clear in your question, now we don´t know if you mean $log_{1}(x) \mbox{ or } log(x)$