1. ## Maximizing Profit

Here is the question:

A store sells portable MP3 players for $100 each and, at this price, sells 120 MP3 players every month. The owner of the store wishes to increase his profit, and he estimates that, for every$2 increase in the price of MP3 players, one less MP3 player will be sold each month. If each MP3 player costs the store $70, at what price should the store sell the MP3 players to maximize profit? I always have trouble figuring out what the function is. Any help is appreciated. 2. A store sells portable MP3 players for$100 each and, at this price, sells 120 MP3 players every month. The owner of the store wishes to increase his profit, and he estimates that, for every $2 increase in the price of MP3 players, one less MP3 player will be sold each month. If each MP3 player costs the store$70, at what price should the store sell the MP3 players to maximize profit?
I'll help walk you through it.

3. x would represent the decrease in MP3 players
so if x were 1, one less MP3 player will be sold

2x would be the increase in price
so if x were 1, there would be a $2 dollar increase at least I think that makes sense 4. Originally Posted by Shapeshift Here is the question: A store sells portable MP3 players for$100 each and, at this price, sells 120 MP3 players every month. The owner of the store wishes to increase his profit, and he estimates that, for every $2 increase in the price of MP3 players, one less MP3 player will be sold each month. If each MP3 player costs the store$70, at what price should the store sell the MP3 players to maximize profit?

I always have trouble figuring out what the function is.
Any help is appreciated.
try this ...

let x = number of $2 increases price = (100 + 2x) number sold = (120 - x) cost = 70(120 - x) can you proceed from here? 5. okay so in the end I got x = 52.5 and I plugged that into the price function: (100 +2x) and I get$205