I havent done antiderivatives in a while, Im wondering if the antiderivative of $\displaystyle 2/(x^2 + 1)$ is just $\displaystyle (ln|x^2 + 1|)/x$ Thanks for the help
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Originally Posted by gidget I havent done antiderivatives in a while, Im wondering if the antiderivative of $\displaystyle 2/(x^2 + 1)$ is just $\displaystyle (ln|x^2 + 1|)/x$ Thanks for the help Note quite $\displaystyle \int \frac{2}{x^2+1}dx=2\tan^{-1}(x)$ If you need the detail let me know. Remember you can always check by taking the derivative and see if you get the original back.
ahhh yes... damnn... thanks for the help!!... thats a newb mistake on my part!
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