f(x)= sinx+2e^x
(I'm suppose to explain why there's no maxima or minima)
$\displaystyle f(x) = \sin{x} + 2e^x$
$\displaystyle f'(x) = \cos{x} + 2e^x$.
Maxima and minima occur where $\displaystyle f'(x) = 0$.
So $\displaystyle 0 = \cos{x} + 2e^x$
$\displaystyle -\cos{x} = 2e^x$.
This isn't solvable exactly, but check their graphs. Do they intersect anywhere?