# Thread: Take the derivative of..

1. ## Take the derivative of..

f(x)= sinx+2e^x

(I'm suppose to explain why there's no maxima or minima)

f(x)= sinx+2e^x

(I'm suppose to explain why there's no maxima or minima)
$\displaystyle f(x) = \sin{x} + 2e^x$

$\displaystyle f'(x) = \cos{x} + 2e^x$.

Maxima and minima occur where $\displaystyle f'(x) = 0$.

So $\displaystyle 0 = \cos{x} + 2e^x$

$\displaystyle -\cos{x} = 2e^x$.

This isn't solvable exactly, but check their graphs. Do they intersect anywhere?