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Math Help - Taylor Series

  1. #1
    Senior Member mollymcf2009's Avatar
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    Taylor Series

    Find the Taylor Series for f(x) centered at a=11\pi

    f(x) = 4 cos(x)

    I got:

    \sum^{\infty}_{n=0} (-1)^n \frac{4(x-11\pi)^{2n}}{(2n)!}

    What did I do wrong on this? I was confused about how to evaluate at 11\pi

    Since at n=0, I did not get a 0, I didn't think I needed to have (2n+1)
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  2. #2
    Moo
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    Hello,

    But cos(0)=1, so you're supposed to get 1, not 0, when n=0.
    Which is the case here.

    Your formula is correct !
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  3. #3
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by Moo View Post
    Hello,

    But cos(0)=1, so you're supposed to get 1, not 0, when n=0.
    Which is the case here.

    Your formula is correct !
    I think you misread my post, I didn't get 0 at n=0, I got cos(11\pi) = -1

    Thanks for verifying my formula!!!
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