This is a tough one... And I really need someones help
Graph the following equation:
x(y-1/2 sgn(x)- 1/2 sgn (x-1)) (x-1) (y-2(x-3)^2) √(2y-y^2 )= 0
Have you considered the cases:
x = 0 , x = 1, and the intervals (-infinity, 0), (0, 1), and (1, infinity)?
at x = 0, for example, you get:
I tried for the first open interval but get a pretty messy implicit relationship. Are you asked to sketch the graph by hand?
Good luck!
Hello, FutureMD2be!
The function is a product of five factors set equal to zero.Graph the following equation:
. .
We can consider each factor separately.
. . . vertical line (the -axis)
. . . vertical line
. . . parabola, opens upward, vertex (3,0)
. . . horizontal lines
Recall the definition: .
We must consider five cases . . .
The graph looks like this:
Code:| 1+ o======= | + * | - - - - - o=======o - - - - | 1 * | =======o-1 |
Now plot all five graphs on the same set of coordinate axes.