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Thread: limit question

  1. #1
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    limit question

    Why is this right

    \frac{1}{2}\frac{\lim}{u\rightarrow0}\frac{\sin[u]}{u}=\frac{1}{2}

    I can make it work with L'Hop's but is it legal to use when u approaches 0 and not infinity
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  2. #2
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    Yep. You can use L'Hop for this case too. There are also other ways of proving this identity.
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  3. #3
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    Thanks Rangr. Can L'Hops be used for u=any N
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  4. #4
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    L'Hops can be used if you have 0/0 or 0/infinity or infinity/infinity or infinity/0. i.e. functions not evaluable at their limits, so we evaluate their slopes when they tend towards these limits.
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