The surface area of a cube is changing at a rate of 8 cm^2/s. How fast is the volume changing when the surface area is 60cm^2? How would i find the length and the rate of change of the length??

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Originally Posted by Tascja The surface area of a cube is changing at a rate of 8 cm^2/s. How fast is the volume changing when the surface area is 60cm^2? How would i find the length and the rate of change of the length?? Volume of cube, of side length is: . Surface area of the same cube is: So: and: . Now when the area is , so: . Also: , so: , hence: RonL