1. definite integral help

$

\int_{0}^1 (x^2+e^x-6)\, dx
$

2. solution

= x^3/3 +e^x -6x = 1/3+e -6 -1

3. Originally Posted by foodmmm
$

\int_{0}^1 (x^2+e^x-6)\, dx
$

Find the antiderivative, without the constant C. You can either do it in one step or separate the function into three terms.

The antiderivative of x^2 is x^3 / 3
The antiderivative of e^x is e^x
The antiderivative of -6 is -6x

Evaluate at 1
Evaluate at 0

Good luck!

4. thanks

thank you so much! i appreciate it.

5. Originally Posted by foodmmm
thank you so much! i appreciate it.