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Math Help - definite integral help

  1. #1
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    definite integral help

    <br /> <br />
\int_{0}^1 (x^2+e^x-6)\, dx<br />
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  2. #2
    MHF Contributor Calculus26's Avatar
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    solution

    = x^3/3 +e^x -6x = 1/3+e -6 -1
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  3. #3
    Senior Member apcalculus's Avatar
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    Quote Originally Posted by foodmmm View Post
    <br /> <br />
\int_{0}^1 (x^2+e^x-6)\, dx<br />

    Find the antiderivative, without the constant C. You can either do it in one step or separate the function into three terms.

    The antiderivative of x^2 is x^3 / 3
    The antiderivative of e^x is e^x
    The antiderivative of -6 is -6x


    Evaluate at 1
    Evaluate at 0

    Subtract the answer at 0 from the answer at 1.

    Good luck!
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    thanks

    thank you so much! i appreciate it.
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  5. #5
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    Quote Originally Posted by foodmmm View Post
    thank you so much! i appreciate it.
    Read this: Table of Integrals

    All these should be in your textbook and/or class notes.
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