# definite integral help

• April 14th 2009, 06:51 AM
foodmmm
definite integral help
$

\int_{0}^1 (x^2+e^x-6)\, dx
$
• April 14th 2009, 06:57 AM
Calculus26
solution
• April 14th 2009, 07:00 AM
apcalculus
Quote:

Originally Posted by foodmmm
$

\int_{0}^1 (x^2+e^x-6)\, dx
$

Find the antiderivative, without the constant C. You can either do it in one step or separate the function into three terms.

The antiderivative of x^2 is x^3 / 3
The antiderivative of e^x is e^x
The antiderivative of -6 is -6x

Evaluate at 1
Evaluate at 0

Good luck!
• April 14th 2009, 07:00 AM
foodmmm
thanks
thank you so much! i appreciate it.
• April 14th 2009, 07:03 AM
mr fantastic
Quote:

Originally Posted by foodmmm
thank you so much! i appreciate it.