antiderivative of [(sinx)^2 - (cosx)^2] / [sinx] dx Do I start by splitting up? use u-sub situation?
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Originally Posted by PMoNEY23 antiderivative of [(sinx)^2 - (cosx)^2] / [sinx] dx Do I start by splitting up? use u-sub situation? You have . Substitute . So you get .
Originally Posted by PMoNEY23 Do I start by splitting up? use u-sub situation? Yes, you can do that. Which are 2 straightforward integrals.
I am up to the part where I have to integrate cotxcscx but with u-substitution I don't get the correct answer so let u=cscx and du=? then what?
Originally Posted by Chop Suey Yes, you can do that. Which are 2 straightforward integrals. Provided you remember what the derivative of is, of course.
Originally Posted by mr fantastic Provided you remember what the derivative of is, of course. Who doesn't? EDIT: @PMoney: Recall that
. Isn't that a bit easier?
Originally Posted by Showcase_22 . Isn't that a bit easier? How?
... I guess it isn't easier after all =S
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