ummm, sort of. You do have to use double angle formulae if that's what you mean.
Think of this:
We already know that (i'll show how Mr F gets his answer since you've never seen it before):
We require an expression for .
from the first identity.
Putting this into the second identity gives:
Going back to our original integral:
The big problem now is the .
Looking at the integral you posted and what I have done here, can you finish this integral off?
(Hint: and ).