I am doing the chain rule in calculus, and this question has got me stuck for a long time now. I am not sure how to approach or solve this, help would be appreciated
The amount of cleaning fluid in a partially filled, spherical tank is given by V = (pi)R(h^2)-pi(h^3)
Where R is the radius of the rank, and h is the depth of the center of the tank. If cleaning fluid is being pumped into the tank, of radius 12m, at a rare of 8 m^3/min, how fast is the fluid rising when the tank is 3/4 full?