Area between curve help?
Let R be the region in the first quadrant bounded above by y=4x+3 and y=x^2+3
A. Find the area of R
I did this part and I got 10.6667. Can anyone confirm this?
B. The line x=c divides R into two regions. If the area of region R to the left of x=c is (2/3) the area of the region, find the value of c.
I need help with this.
C. The line y=a divides R into two regions of equal area. Find the value of a.
Thank you all!
Well I understand what to do for part B, I just don't know how to go about doing it (other than guess and check of course). For part C, would it be easier to do things with respect to y?
For part B, evaluate the integral .
Originally Posted by GlobalCooling
You should get . You know this has to be equal to 2/3 of the area, which is 64/9. All you have to do is solve for c.