∫10 (e^(-9x)) / (e^(-9x) + 6)) dx

8

Evaluate the integral using the fundamental theorem of calculus.

I don't know how to do rational numbers, i know that it is complex

because of the quotient rule for derivatives

anyway, here's mywork so far

∫from 10 to 8 (e^(-9x))/(e^(-9x)) +∫from 10 to 8 (e^(-9x))/6

∫from 10-8 (1) +∫from 10 to 8 (e^(-9x))/6

2 + 1/6∫from 10 to 8 (e^(-9x))

2 + 1/6 [((e^(-90+1))/(-90+1)) - ((e^(-72+1))/(-72+1))]

2 + 1/6 [(e^(-89)/(-89)) - (e^(-71)/(-71))]

this is wrong,

please help

thanks,

brittany