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Math Help - [SOLVED] Prove this limit...

  1. #1
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    [SOLVED] Prove this limit...

    Prove using limit definition:
    lim 1/x = 1/c, c is not equal 0
    x→ c
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    Quote Originally Posted by thaliaj_df View Post
    Prove using limit definition:
    lim 1/x = 1/c, c is not equal 0
    x→ c
    you need to show that for every \epsilon > 0, there is some \delta > 0, such that |x - c| < \delta implies \left| \frac 1x - \frac 1c \right| < \epsilon

    Now, \left| \frac 1x - \frac 1c \right| = \left| \frac {c - x}{xc} \right| = \frac {|x - c|}{|xc|}

    Now, can you finish up?
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    Thnx

    Thanks a lot...
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  4. #4
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    Question

    I wanted to ask a question though, is it correct to rearrange values of the x and c, it being in absolute brackets.... does it make a difference... Please answer
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  5. #5
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    Quote Originally Posted by thaliaj_df View Post
    Prove using limit definition:
    lim 1/x = 1/c, c is not equal 0
    x→ c
    Also asked and replied to here: http://www.mathhelpforum.com/math-he...efinition.html
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  6. #6
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    Quote Originally Posted by thaliaj_df View Post
    I wanted to ask a question though, is it correct to rearrange values of the x and c, it being in absolute brackets.... does it make a difference... Please answer
    |x - c| = |c - x| by definition of | |.
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