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Math Help - Definite Integral Problem-Work needs checked

  1. #1
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    Definite Integral Problem-Work needs checked

    \int_{x=0}^{x=1} (x^2+e^x-6)dx

    \int (x^2+e^x-6)dx

    \frac{x^3}{3}+e^x-6x+c

    \int_{x=0}^{x=1} (x^2+e^x-6)dx

    \frac{x^3}{3}+e^x-6x\int_{x=0}^{x=1}

    \frac{1^3}{3}+e^1-6(1)

    =-5\frac{2}{3}+e

    \frac{0^3}{3}+e^0-6(0)

    =e

    -5\frac{2}{3}+e-e

    =-5\frac{2}{3}
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  2. #2
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by Jim Marnell View Post
    \int_{x=0}^{x=1} (x^2+e^x-6)dx

    \int (x^2+e^x-6)dx

    \frac{x^3}{3}+e^x-6x+c

    \int_{x=0}^{x=1} (x^2+e^x-6)dx

    \frac{x^3}{3}+e^x-6x\int_{x=0}^{x=1}

    \frac{1^3}{3}+e^1-6(1)

    =-5\frac{2}{3}+e

    \frac{0^3}{3}+e^0-6(0)

    =e

    -5\frac{2}{3}+e-e

    =-5\frac{2}{3}

    e^0 \neq e
    <br />
e^0 = 1
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