Originally Posted by

**isuckatcalc** Thanks, that helps a lot. If I use this test, and I get an indeterminate form, I can then use L' Hopital's rule, right?

I'm having trouble with one in particular though.

I'm looking at:

(ln(x))^2 / x^3

So I compare it to 1/x^2.

And when I divide the two, I get:

(ln(x))^2 / x. and as x-> inf, they both go to inf. So use L' hopital's rule and get

2ln(x)/x. still both go to inf. so use it again to get

2/x. but that goes to 0. so that doesn't help me at all, does it? What am I doing wrong?