, c=0

If I did this right, where do I go from here?? Thank you.

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- April 12th 2009, 09:28 AMsaiyanmx89need help with a/(1-r) form
, c=0

If I did this right, where do I go from here?? Thank you. - April 12th 2009, 09:31 AMTheEmptySet
- April 12th 2009, 09:34 AMPlato
- April 12th 2009, 09:39 AMsaiyanmx89
you mean I didn't need to go any further with it?

- April 12th 2009, 09:42 AMPlato
- April 12th 2009, 09:57 AMsaiyanmx89
oh yea. the x^2, which is why I must use= (x/2)^2

But, where do I go from here:

= ?? - April 12th 2009, 10:01 AMJhevon
- April 12th 2009, 10:05 AMsaiyanmx89
could I use the Ratio Test on

- April 12th 2009, 10:28 AMJhevon
- April 12th 2009, 01:36 PMsaiyanmx89
so, by using the Alternating Series, I can take the absolute value of the function leaving me with (x^2/4) or (x/4) ??? I'm not sure which...

- April 12th 2009, 01:53 PMPlato
- April 12th 2009, 01:54 PMsaiyanmx89
x^2/4