By differentiating we get What's the substitution?
you want u and du to substitute for everything inside the integral.
1. You can do this by setting u= x^3-3x which gives du=3(x^2-1)dx get rid of the 3 by dividing both sides by it and you'll get 1/3du= (x^2-1)dx which is what you want.
2. Substitute into integral:
should get something like this by taking the 1/3 out as a constant
1/3 integral e^u du , which shows everything is accounted for from the original.
3. Integrate. When you do you should get 1/3 e^u + C
4. Plug u back in and you're done.
1/3 e^(x^3-3x) + C
Is it clear now?